What is the sum of the n terms of the series 6 + 24 + 96 + 384 + . . ? hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio. sn = −6(4n − 1) sn = 6(1 − 4n) sn = 2(4n − 1) cap s sub n equals start fraction six left parenthesis four to the power of n end power minus one right parenthesis over n minus one end fraction