What is the length of a hypotenuse when the legs are 5 and 12

By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse

So, hypotenuse = 13

9.8? i'm not really sure