The proof that δabc ≅ δcda is shown.

given: ∥ and ∥
prove: δabc ≅ δcda

what is the missing reason in the proof?

statements reasons
1. ab ∥ cd; bc ∥ da 1. given
2. quadrilateral abcd is a ▱ 2. definition of parallelogram
3. ab ≅ cd; bc ≅ da 3. opposite sides of a parallelogram are ≅
4. ac ≅ ac 4. reflexive property
5. δabc ≅ δcda 5. ?

a. perpendicular bisector theorem

b. pythagorean theorem

c. hl theorem

d. sss congruence theorem

D. SSS congruence theorem

Step-by-step explanation:

In the given proof we have in ΔABC ≅ ΔCDA

AB ≅ CD; BC ≅ DA[ opposite sides of a parallelogram are ≅]

AC ≅ AC[ reflexive property]

Therefore by SSS postulate of congruence  ΔABC ≅ ΔCDA.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

$9.41

step-by-step explanation: