How many different ways when we take 7 numbers from 49 lottery numbers, and from 7 of these numbers there are 3 correct numbers? (kombination)

⁴⁹C₇ = 85,900,584 this is the total ways if we select 7 numbers out of 49.

among that number only 3 are correct, so ⁷C₃ = 35 are correct

If ⁷C₃ are correct, means the remaining incorrect are ⁽⁴⁹⁻⁷⁾C₄ =⁴²C₄
And the total ways of getting 3 correct numbers is :

⁷C₃ x ⁴²C₄ = 3,917,550

Your answer would be ahere is how: perimeter is how long all the sides are. in a rectangle, there are two sets of parallel sides. so, to find this, we would to the following.(15x2)+(4x2)30+838if you have questions ask! and mark me brainliest! i really wanna level up : 3