Team a and b love to play pickup basketball. there are no fouls and no three-pointers, so all shots are worth 2 points. the only problem is team a always wins. they typically play games to 100 and team b loses by 10 points. that is, the typical final score is team a 100, team b 90.
so, they decide to increase the point value of each basket for team b to 2.2 points. based on the typical results above, what effect is this most likely to have? a)the teams will tend to score the exact same number of points. b)team a will still tend to win, by 1 point instead of 10. c)team b will now tend to win by a margin of 1 point. d) team b will now tend to win by 10 points.

The correct option is B) Team A will still tend to win, by 1 point instead of 10.

Step-by-step explanation:

Consider the provided information.

There are no fouls and no three-pointers and all shots are worth 2 points.

The typical final score is Team A 100, Team B 90.

The final score of team A is 100, that means the number of shots by team A is 50 (50 × 2 = 100).

Similarly, the final score of team B is 90, that means the number of shots by team B is 45 (45 × 2 = 100).

They decide to increase the point value of each basket for Team B to 2.2 points.

Now, multiply 2.2 with 45.

45 × 2.2 = 99

Thus, the total score of team B is 99 and total score of team A is still 100. Therefore, team A will still tend to win, by 1 point.

Hence, the correct option is B) Team A will still tend to win, by 1 point instead of 10.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.