Compute the permutations and combinations. a farmer buys 2 cows, 3 pigs, and 10 sheep from a seller who has 7 cows, 4 pigs, and 10 sheep. how many choices of animals does he have?

Total number of ways = 84

Step-by-step explanation:

Number of choices farmer has for cows = 2 out of 7

Number of choices farmer has for pigs = 3 out of 4

Number of choices farmer has for cows = 10 out of 10

All these three groups of different animals can make different groups when taken together

Thus, Total number of ways = 21 × 4 × 1

⇒  Total number of ways = 84

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

hi there, i would be interested to you with your test, may you add the questions and answer options.

- : )