How do i solve the running time of a train between two terminals is 48 minutes, and there is a 7-minutes layover at each terminal. if a train leaves one terminal at 11: 00 a. m. this train is due back at the same terminal at what time? ?

At First lets say the train is at terminal A
To get to terminal B ( next terminal )
It takes him 48 minutes
Then spend 7 more minutes at terminal B
( 48 + 7 = 55 minutes spent so far )

Then spend 48 more minutes from terminal B to go back to terminal A
( 55+ 48 = 103 minutes spent)

Convert minute to hour ( divide by 60 )

103/60 = 1.7 h

11 + 1.7 = 12.7
So the time would be 7 minutes past 12
12:07 pm.

You would need a laid out graph for this but could you provide a picture of just a graph? i can give stepssolve for y.subtract 4xdivide by -1 (opposites)graph slope intercept formcheck each point to see if it’s on the graph