![\bf [cos(\theta)+cos(\theta)]^2+[cos(\theta)+cos(\theta)]^2\implies [2cos(\theta)]^2+[2cos(\theta)]^2 \\\\\\ 2^2[cos(\theta)]^2+2^2[cos(\theta)]^2\implies 4[cos(\theta)]^2+4[cos(\theta)]^2 \\\\\\ 8[cos(\theta)]^2\iff 8cos^2(\theta)](/tpl/images/0402/6175/757a8.png)
!
these are the options
a. sin^θ
Mathematics, 04.12.2019 07:31 lollipop83
(cos θ + cos θ)2 + (cos θ + cos θ)2
!
these are the options
a. sin^θ
b.4
c.8cos ^2 θ
d. cos ^θ
Answers: 3
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You know the right answer?
(cos θ + cos θ)2 + (cos θ + cos θ)2
!
these are the options
a. sin^θ
!
these are the options
a. sin^θ
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