Lis the midpoint of segment cd. if cl=13x+8 and ld=23x−4 , find the length of segment cd.

CD = 47.2 units

Step-by-step explanation:

Given:-

- L is the mid-point of line segment CD

- Where,

                               CL = 13x + 8

                               LD = 23x - 4

Find:-

Find the length of segment CD.

Solution:-

- Since the point L is the midpoint of the CD then two expressions given CL and LD must add up to CD.

                               CD = CL + LD

                               CD = (13x + 8) + (23x - 4)

                               CD = 36x + 4

- To determine the value of x we can also say that CL and LD must be equal because L is the common mid-point on the line segment CD. So we can write:

                               CL = LD

                               13x + 8 = 23x - 4

                               12 = 10x

                               x = 1.2 units

- Now substitute the value of x in the expression developed for CD as follows:

                              CD = 36*(1.2) + 4

                              CD = 43.2 + 4

                              CD = 47.2 units

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step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.