Line ab passes through points a(–6, 6) and b(12, 3). if the equation of the line is written in slope-intercept form, y = mx + b, then m =–1/6 and b =
a.-6
b.-5
c.5
d.6
timed hurry pls

5

Step-by-step explanation:

I just took it on edge

m=−2, b=18

eqn. of a straight line with known co-ordinates

(x1,y1), (x2,y2)

is given by the formula

y−y1x−x1=y2−y1x2−x1

for A(6,6), B(12,3)

y−6x−6=12−63−6

y−6x−6=6−3=−2

y−6=−2(x−6)

y=6+(−2x)+12

y=−2x+18

m=−2, b=18

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5