Mathematics, 18.09.2019 08:30 treytonmesser

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). what is the standard form of the equation for this line?
a. 2x – 5y = –15
b. 2x – 5y = –17
c. 2x + 5y = –15
d. 2x + 5y = –17

Answers: 1

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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7...

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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). what is the standard form of the equation for this line? a. 2x – 5y = –15 b. 2x – 5y = –17 c. 2x + 5y = –15 d. 2x + 5y = –17

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Another question on Mathematics

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). what is the standard form of the equation for this line?
a. 2x – 5y = –15
b. 2x – 5y = –17
c. 2x + 5y = –15
d. 2x + 5y = –17