H(x) = 2x2 + 26 the fundamental theorem of algebra tells you that this polynomial function has x roots ?

From the fundamental Theorem of Algebra the given polynomial function has exactly 2 roots.

The fundamental Theorem of algebra states that:

If P(x) is a polynomial of degree n≥1 then P(x)=0 has exactly n roots, including multiplicity and complex roots.

Hence here we have a polynomial function h(x) as:

As the polynomial h(x) is of degree 2.

Hence, the polynomial h(x) has 2 roots.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.