![\bf \sqrt[{{ n}}]{z}=\sqrt[{{ n}}]{r}\left[ cos\left( \frac{\theta+2\pi k}{{{ n}}} \right) +i\ sin\left( \frac{\theta+2\pi k}{{{ n}}} \right)\right]\quad k\ roots\\\\ -------------------------------\\\\](/tpl/images/0430/9812/1fddc.png)
![\bf \sqrt[3]{64}[cos(330^o)+i\ sin(330^o)] \\\\\\ \sqrt[3]{64}\left[cos\left( \frac{330+360(0)}{3} \right) + i\ sin\left( \frac{330+360(0)}{3} \right) \right] \\\\\\ 4[cos(110^o)+i\ sin(110^o)]\implies 4(-0.34202014)+4(0.9396926) \\\\\\ \approx -1.37 + 3.76i\impliedby \textit{first root, k = 0}\\\\ -------------------------------\\\\](/tpl/images/0430/9812/54a70.png)
![\bf \sqrt[3]{64}[cos(330^o)+i\ sin(330^o)] \\\\\\ \sqrt[3]{64}\left[cos\left( \frac{330+360(1)}{3} \right) + i\ sin\left( \frac{330+360(1)}{3} \right) \right] \\\\\\ 4[cos(230^o)+i\ sin(230^o)]\implies 4(-0.6427876)+4(-0.7660444) \\\\\\ \approx -2.57 -3.06i\impliedby \textit{second root, k = 1}\\\\ -------------------------------\\\\](/tpl/images/0430/9812/f9de3.png)
![\bf \sqrt[3]{64}[cos(330^o)+i\ sin(330^o)] \\\\\\ \sqrt[3]{64}\left[cos\left( \frac{330+360(2)}{3} \right) + i\ sin\left( \frac{330+360(2)}{3} \right) \right] \\\\\\ 4[cos(350^o)+i\ sin(350^o)]\implies 4(0.98480775)+4(-0.1736481) \\\\\\ \approx 3.94 -0.695i\impliedby \textit{third root, k = 2}](/tpl/images/0430/9812/5a20c.png)
cube root 64(cos330+isin330)
show work...
Answers: 3
Another question on Mathematics
Mathematics, 21.06.2019 18:50
The trigonometric ratios sine and secant are reciprocals of each other
Answers: 2
Mathematics, 22.06.2019 00:00
4. bob solved the inequality problem below incorrectly. explain his error and redo the problem showing the correct answer. −2x + 5 < 17 −2x + 5-5 < 17-5 -2x/-2 < 12/-2 x < -6
Answers: 2
You know the right answer?
Questions
Mathematics, 03.02.2020 00:58
Chemistry, 03.02.2020 00:58
English, 03.02.2020 00:58
Health, 03.02.2020 00:58
History, 03.02.2020 00:58
Chemistry, 03.02.2020 00:58
Mathematics, 03.02.2020 00:58
Mathematics, 03.02.2020 00:59
Mathematics, 03.02.2020 00:59
English, 03.02.2020 00:59
Mathematics, 03.02.2020 00:59
