Pleassee timedd
from x = 0 to x = 2, which of the following best describes the growth of the two functions below?
first graph is y=5x second graph is y=5^x

y=5x grows slower than y = 5^x

Step-by-step explanation:

In first graph y=5x, From x = 0 to x = 2

When x=0 , the value y= 5(0)= 0

When x=2 , the value y= 5(2)= 10

WE analyze the second graph

y=5^x from x=0 to x=2

When x=0 , the value y= 5^(0)= 1

When x=2 , the value y= 5^(2)= 25

The second graph is increasing rapidly

the first function grows slower than second function

y=5x grows slower than y = 5^x

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

idk wbu

step-by-step explanation: