Which values are in the solution set of the compound inequality –8 < 3x + 7 ≤ 10? check all that apply.

–15
–5
–3
0
1
3

Options C, D, and E

Step-by-step explanation:

To get the answer of this question we will simplify the inequality first.

-8 < 3x + 7 ≤ 10

We subtract (-7) in the given inequality

= -8 - 7 < (3x + 7) - 7 ≤ 10 - 7

= -15 < 3x ≤ 3

Now we will divide the inequality by 3

=

= -5 < x ≤ 1

Now the options which lie between (-5) to 1 and equal to 1 will be the solution set.

So the options will be (-3), 0 and 1

Options C, D, E will be the solutions.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

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step-by-step explanation: