∆abc has vertices at a(12, 8), b(4, 8), and c(4, 14). ∆xyz has vertices at x(6, 6), y(4, 12), and z(10, 14). ∆mno has vertices at m(4, 16), n(4, 8), and o(-2, 8). ∆jkl has vertices at j(14, -2), k(12, 2), and l(20, 4). are congruent. a is a single rigid transformation that maps the two congruent triangles.

1- a) triangle abc and triangle xyz
b) triangle abc and triangle mno
c) triangle jkl and triangle abc
d) triangle mno and triangle xyz

2- a) reflection
b) dilation
c) rotation
d) translation

Option B is correct.

Rotation.

Step-by-step explanation:

Given ∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14). ∆MNO has vertices at M(4, 16), N(4, 8), O(-2, 8). ∆JKL has vertices at J(14, -2), K(12, 2), and L(20, 4).

we have to tell the two triangles which are congruent.

From the graph we see

AB=MN=8 units

BC=OM=6 units

∠ABC=∠OMN=90°

By SAS rule, ΔABC≅ΔMNO.

Option B is correct.

By distance formula,

All the three sides are of same length and the triangles are congruent therefore, the rotation is a single rigid transformation that results into two congruent triangles.

answer: a.   one is a factor of every whole number since every number is divisible by itself.