Answer quickly i do not need an explanation just the right answer
which equation is the inverse of 5y+4=(x+3)^2+1/2 ?
a. y = 1/5x^2 + 6/5x + 11/10
b. y = 3 +- sr5x+7/2
c. -5y - 4 = -(x+3)^2 - 1/2
d. y = -3 +- sr5x+7/2
"sr" means square root and "+-" is obviously "plus or minus"

Step-by-step explanation: Given equation .

We need to find it's inverse.

In order to find the inverse, we need to switch x and y's and solve for y.

Step 1: Switching x and y's, we get

Step 2: Solving it for y.

Subtracting from both sides, we get

Taking square root on both sides, we get

Subtracting 3 from both sides, we get

Switching sides, we get

Therefore, correct option is D option .

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

i can you answer this question sweetie!

step-by-step explanation: