Is square root 1 minus sine squared theta = cos θ true? if so, in which quadrants does angle θ terminate?

false

true; quadrants i & iv

true; quadrants ii & iii

true; quadrants i & iii

√(1-sin^2(theta))= cos(theta)
If we square the equation, than we have:
1-sin^2(theta) = cos^2(theta)
sin^2(theta) + cos^2(theta) = 1 which is TRUE.
The another answer is in the quadrants where sine is positive: I, IV
That leads to the B