Aball is thrown into the air with an upward velocity of 48 ft/s. its height h in feet after t seconds is given by the function h=-16t^2+48t+6. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. what is the ball’s maximum height? a. 3 s; 6 ft b.1.5 s; 54 ft c. 1.5 s; 114 ft d. 1.5 s; 42 ft

time = -48/(2*-16) = 1.5 seconds

height = -16(1.5)^2+48(1.5)+6 = 42 ft

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.