Quadrilateral mnpq has vertices at (−3, 5), (−4, 6), (−5, 7), and (−6, 8). if the quadrilateral mnpq is reflected over the x−axis, what will the new coordinates be?
(3, 5), (4, 6), (5, 7), (6, 8)
(5, −3), (6, −4), (7, −5), (8, −6)
(−3, −5), (−4, −6), (−5, −7), (−6, −8)
(3, −5), (4, −6), (5, −7), (6, −8)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

i think it might be a but you might want a second opinion