The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = (x – 1). what is the slope-intercept form of the equation for this line?

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

here the answers ur welcome also plz mark as brainliest if someone else anwers

all of them are elements inside set of real numbers since none of them appears to have complex number form.

hope this .

r3t40

perpendicular to x*4 means it's y = -1/4*x+k

so for y = 7 and x = 2

we have 7 = -1/4*2 + k so k = 7.5

so the equation is   y = -1/4x + 7.5