The following work represents an attempt to find the equation of the parabola which has a vertex of (0, 0) and passes through the point (1, 3). is the work correct? if not, what is the error?
y=a(x-h)^2+k
0=a(0-1)^2+3
-3=a
y=a(x-h)2+k
y=-3(x)^2
y=-3x^2
a.
the equation is correct.
b.
a = –3 should have been a = 9.
c.
0=a(0-1)^2+3 should have been 3=a(1-0)^2+0
d.
-3x^2 should have been 23x^2 + 3.x

whatever you can spend with $11.53 or under.

step-by-step explanation:

20 - 8.47 = 11.53. take away the money he used for lunch from the starting amount of 20.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2