The side lengths of triangle abc are 3, 4, and 5. which set of ordered pairs form a triangle that is congruent to triangle abc?

FORMULA:
AREA=     AC x h
        ----------------------
                    2
PERIMETER= AB+BC+CA

AREA   =   SQUAREROOT       
                  S(S-AB)(S-BC)(A-CA)

S= AB+BC+CA=   P
     -----------------   -----
               2             2

FOR THE COMPLETE SOLUTION PLEASE SEE THE PICTURE. THANKS.

Ican't read this very blury

Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.