How would you write this expression as a sum or difference? 1 5 log3x + log3y log3x5 – log3y 1 5 (log3x + log3y)

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it

if your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

max = c - (b2 / 4a).

the first step is to determine whether your equation gives a maximum or minimum.

-x2 + 4x - 2.     thats an example hope it