Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

a(n) = –3 + (n – 1)(–2.2)

N is going to be the term u want to find

the formula : an = a1 + (n-1)da1 is going to be ur first term...so ur first term is -3or u can find it by subbing in 0 for n

4th term...n = 4
a4 = -3 + (4-1) * -2.2
a4 = -3 + 3(-2.2)
a4 = -3 - 6.6
a4 = -9.6 <== 4th term

tenth termn = 10
a10 = -3 + (10 - 1) * -2.2
a10 = -3 + 9(-2.2)
a10 = -3 - 19.8
a10 = -22.8 <== 10th term

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Bi’m pretty sure hope it works