![\bf 2sec^2(\theta )-tan(\theta )-3=0 \\\\\\ 2[1+tan^2(\theta )]-tan(\theta )-3=0\implies 2+2tan^2(\theta )-tan(\theta )-3=0 \\\\\\ 2tan^2(\theta )-tan(\theta )-1=0\implies [2tan(\theta )+1][tan(\theta )-1]=0\\\\ -------------------------------\\\\](/tpl/images/0290/5731/dca8f.png)
How can you determine which quadrant an equation falls in?
for the equation 2sec²θ - ta...
Mathematics, 05.10.2019 19:00 smartowl101
How can you determine which quadrant an equation falls in?
for the equation 2sec²θ - tanθ - 3 = 0
the answers of θ falls in quadrant 2 and 4.
my understanding is that this equation is positive therefore it will fall under quadrant 1 and 3.
Answers: 1
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