What are the zero(s) of the function f(x)=4x2-36x over x-9?

x=0 is the zero of the given function

Step-by-step explanation:

To find zeros of the function we replace f(x) with 0

then we solve for x

Now we factor the numerator 4x^2 -36x

Cancel out x-9 at the top and bottom

0=4x (divide by 4 on both sides)

x=0

So x=0 is the zero of the given function

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°