How many solutions are there to the equation below?

4(x-5)=3x+7

4(x - 5) = 3x + 7
4x - 20 = 3x + 7
x - 20 = 7
x = 27

Hence there is only one solution. These types of equations are called linear equations and linear equations have a degree of 1, which means they have only one solution.

To help answer your question, a quadratic equation (an equation of degree 2) has 2 solutions, 1 solution, or no solutions (imaginary solutions).

I hope this helps ya.

4(x-5)=3x+7

Let's first solve the parentesis.

4x - 20 = 3x + 7

Move the unknown termsnto the left of the equal with changed sign and the same for known terms but to the right of the equal.

4x - 3x = 7 + 20

x = 27