Complete the square to rewrite y = x2 – 6x + 5 in vertex form. then state whether the vertex is a maximum or a minimum and give its coordinates. a. maximum at (3, –4) b. minimum at (3, –4) c. minimum at (–3, –4) d. maximum at (–3, –4)

B.Minimum at (3, –4)

Step-by-step explanation:

Given is a quadratic function as

Considering the first two terms, we find that if we add 9 we can make it a perfect square

Hence add and subtract 9 to right side

This is in vertex form

Vertex = (3,-4)

Since coefficient of leading term of x is positive, the parabola is open up and hence minimum is at (3,-4)

Option B,

it is probably the graph on the bottom right.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome