The age of mary, jo, and larry have a sum of 120. mary's age is three times jo's age, and larry's age is 5 less than jo's age. find the age's of mary, jo, and larry. and fill in these blanks. if mary's age is 75 then jo's and larry's age

Let  M = Mary's age.
Let J = Jo's age
Let L = Larry's age.

The sum of their ages is 120. Therefore
M + J + L = 120               (1)

Mary's age is three times Jo's age. Therefore
M = 3J                             (2)

Larry's age is 5 less than Jo's age. Therefore
L = J - 5                          (3)

Substitute (2) and (3) into (1).
3J + J + (J-5) = 120
3J + J + J - 5 = 120
5J - 5 = 120
5J = 120 + 5 = 125
J = 125/5 = 25

Therefore
J = 25,  M = 3J = 75,  L = J - 5 = 20
 Mary's age = 75;  Jo's age = 25;  Larry's age = 20

If Mary's age is 75, then Jo's age is 25, and Larry's age is 20.

Assume Jo's age is x.

Mary is 3x, Larry is x-5

So x + 3x + (x-5) = 120

x = 25

So Jo is 25, Mary is 25*3 = 75, Larry is 25-5 = 20

Igot 108 hope that’s right !

No he does not because he can only cover 12 square feet from 15 square feet which he will still need 3 more. this is because if 3×5=15 square feet and 15-12=3 which thats the answer