Find the equation in slope intercept form for the line that is perpendicular to the line 10x- 5y=3 and passes through the point (4,-3)

Hello:

10x -5y =3

5y = 10x-3

y =2x -3/5( slope : 2)
the equation is : y = ax+b
the slope is a : a×(2) = -1( perpendicular to a line with a slope of2)
a = -1/2          y=(-1/2)x+b
the line that passes through (4, -3) : -3 = (-1/2)(4)+b
b = -1
 the equation is :  y  = (-1/2)x-1

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1