Asurveyor is standing 50 feet from the base of a building. the angle of elevation to the top of the building is 60°. approximately how tall is the building?

We have to find how tall is the building if a surveyor is standing 50 ft from the base of the building and the angle of elevation to the top of the building is 60°.tan 60° = h / 501.732 = h / 50h = 50 · 1.732h = 86.6 ft. The height of the building is 86.6 ft.

The total would be 40.53