Suppose a right triangle has a hypotenuse of length 2 and one angle is 30 degrees. find the length of the other two sides

Answer : The length of the other two sides AB and BC is, 1 and

Step-by-step explanation :

First we have to calculate the angle A.

In right angle ΔABC,

Let ∠B = 30°

∠C = 90°

As we know that, the sum of interior angle of a triangle is 180°

∠A + ∠B + ∠C = 180°

∠A + 30° + 90° = 180°

∠A = 60°

Now we have to calculate the length AB in right angle ΔABC.

According to trigonometric function:

Given:

Hypotenuse = 2

As, we know that

Now we have to calculate the length BC in right angle ΔABC.

According to trigonometric function:

Given:

Hypotenuse = 2

As, we know that

Thus, the length of the other two sides AB and BC is, 1 and

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3