Four consecutive multiples of 6 yield a sum of 156. what are these multiples?

Let x be the first number:
1st number: = x
2nd consecutive multiple of 6 = x+6
3rd consecutive multiple of 6 = x+12
4rth consecutive multiple of 6 = x+18
Their sum = 156 → x+(x+6)+(x+12)+(x+18) = 156
4x +30 = 156
4x = 120 and x = 30

The numbers are: 30,36,42,48