Given the functions f(n) = 11 and g(n) = (three fourths)n − 1, combine them to create a geometric sequence, an, and solve for the 9th term.

an = (11 • three fourths)n − 1; a9 ≈ 24.301
an = 11(three fourths)n − 1; a9 ≈ 1.101
an = 11 + (three fourths)n − 1; a9 ≈ 11.100
an = 11 − (three fourths)n − 1; a9 ≈ 9.900

We are given two functions:
f(n) = 11
g(n) = (3/4) ^(n-1)
I have rewritten the functions to their correct form. Notice that the term (n - 1) is the exponent of 3/4.

We are asked to combine the two functions to model a geometric sequence and solve for the 9th term.

The general formula for a geometric sequence is
an  = a1 r^(n - 1)

From the given functions, we can set
f(n) = a1 = 11
and 
g(n) = r^(n - 1) = (3/4)^(n - 1)

Substituting to the general formula of a geometric sequence, the result is
an = 11 (3/4)^(n - 1)

Solving for the 9th term
a9 = 11 (3/4)^(9 - 1)
a9 = 1.101

The answer is the second option.

How many people are we starting with? i will answer it's just i need to divide 8 by the total amount of people to get how many tables

The correct answer is: 2