The equation of a circle is (x - 3)^2 + (y + 2)^2 = 25. the point (8, -2) is on the circle.
what is the equation of the line that is tangent to the circle at (8, -2)?
y = 8
x = 8
x = 3
y = 3

From the equation, you can see that (3,-2) is the center of the circle (the terms are 0 for those x,y values). The mentioned point has the same y value as the center. That's good news, because it tells us that the tangent line is exactly vertical. The x coordinate is given as x=8. Vertical lines have an equation of x=... so x=8 is the right answer.