What is the 25th term of this arithmetic sequence? 3, 9, 15, 21, 27, …

25th Term of the Given Sequence is 147.

Step-by-step explanation:

We are given with an arithmetic sequence: 3 , 9 , 15 , 21 , 27 , ...

We have to find 25th term of the sequence.

First term of the sequence , a = 3

Common difference of the sequence , d = 9 - 3 = 6

We know that nth term of Arithmetic Sequence is given as below,

So,

25th term of the sequence ,

Therefore, 25th Term of the Given Sequence is 147.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.