If you have a rectangular rug whose perimeter is 26 feet and the length is three feet more than the width, what are the dimensions of the rug? (p=2w+2l)

You have the lenght that is 3w, so lenght is the third part and the width the first part.

You assign the value 3 to l and the value 1 to w

Of course, you have to do the "semiperimeter" or you'll get double sides.

Semiperimeter = 26/2 = 13 ft.

You sum the parts

3+1 = 4

13/4 = 3,25 ft. (1 part)

3,25*1 = 3,25 ft. (Widht)

3,25*3 = 9,75 ft. (Lenght)

You can solve it even as an equation

You put x the lenght, the width is 3x

x+3x = 13

4x = 13

x = 3,25

w = 3*3,25 = 9,75

Hello!
volume of sphere =4/3.pi.r^3