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![\dfrac\partial{\partial y}[1-\sin x\tan y]=-\sin x\sec^2y](/tpl/images/0289/2265/4219e.png)
![\dfrac\partial{\partial x}[\cos x\sec^2y]=-\sin x\sec^2y](/tpl/images/0289/2265/a9a0e.png)
such that, by the chain rule,
, we have
yields
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Solve (1-sinxtany)dx + (cosxsec^2y)dy = 0...
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