X2=12x-5 by completing scquare. which is the solutions set of the equation

X²=12x-5
minus 12x both sides
x²-12x=-5
take 1/2 of the linear confident and square it
-12/2=-6, (-6)²=36
add that to both sides
x²-12x+36=-5+36
factor perfect square
(x-6)²=31
sqrt both sides, remember to take positive and negative roots
x-6=+/-√31
x=6+/-√31

the solutions are 6+√31 and 6-√31