Arectuangular room is 2 meters longer then its width its perimeter is 21.2

perimeter = 2L + 2W

L=w+2

21.2=2(w+2) +2w

21.2 = 2w+4+2w

21.2 = 4w+4

17.2 = 4w

w=4.3

l=4.3+2 =6.3

check:

6.3 +6.3+4.3+4.3 = 21.2

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane