Solve the system by the elimination method.
x + y - 6 = 0
x - y - 8 = 0
when you eliminate y , what is the resulting equation?

2x = 14

Step-by-step explanation:

Solving the equation us in elimination method,

x + y - 6 = 0...1

x - y - 8 = 0...2

From 1,

x+y = 6...3

x-y = 8...4

To eliminate y, we will add equation 3 and 4 since both the signs attached to y are different.

2x=6+8

2x = 14 (This will be the resulting equation)

To get the variables x, we will divide both sides of the resulting equation by 2

x = 14/2

x = 7

Substituting x = 7 into eqn 3

7 + y = 6

y = -1

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2