The proof that δacb ≅ δecd is shown. given: ae and db bisect each other at c. prove: δacb ≅ δecd what is the missing statement in the proof? ∠bac ≅ ∠dec ∠acd ≅ ∠ecb ∠acb ≅ ∠ecd ∠bca ≅ ∠dca

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD

Answer with explanation:

Given: It is given that , in ΔACB and ΔE CD , A E and DB bisect each other at C.

To Prove:  ΔA CB ≅ ΔE CD

Proof: In  ΔA CB ,and ΔE CD

A E and DB bisect each other at C.

AC=CE -------[Given]

          BC=CD-----[Given]

       ∠A CB = ∠E CD →→[Vertically opposite angles]

→∠A CB ≅ ∠E CD ⇒⇒[S A S]

Option C: →→∠A CB ≅ ∠E CD -------[missing statement in the proof]

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

1) is right

step-by-step explanation: