Someone solve this asap and give answer as a square root

Given pyramid with a regular hexagonal base,
side length=6 cm
Height = 4 cm

We need to find the area of the hexagonal base.  First step is to find the apothm,
a=side*( 
=6*3/2=9
So the area of each equilateral triangle making up the base
=base*apothem/2
=6 *9/2
=27
The area of base = 6 area of each triangle
=6*27
=162

Volume of pyramid = area of base * height /3
=162*4/3
=216

Answer is a not really sure tho