Mathematics, 29.01.2020 16:02 yaniravivas79
Solve for x to the nearest hundredth: 4.15x+29.35=7.29x+189.21
Answers: 3
Mathematics, 21.06.2019 21:20
In 2009, there were 1570 bears in a wildlife refuge. in 2010, the population had increased to approximately 1884 bears. if this trend continues and the bear population is increasing exponentially, how many bears will there be in 2018?
Answers: 2
Mathematics, 22.06.2019 00:30
$5400 is? invested, part of it at 11? % and part of it at 8? %. for a certain? year, the total yield is ? $522.00. how much was invested at each? rate?
Answers: 1
Mathematics, 22.06.2019 02:20
Jenny invests $2,000 at an interest rate of 5%. the amount of money, me, in jenny's account after tyears can be represented using the equation ma-2000(1.05). if jenny would have invested the same amount of money at the same interest rate four years ago, the equation representing the amount of money mo. in her account would be represented using the equation! mg = 2000(105)*** which of the following is equivalent to mp? 2000(105) om- 1.05 2000(1.05) mo 1059 mp-2000(1.05) (105) mp - 2000(1.05) + (1.05)
Answers: 1
Solve for x to the nearest hundredth: 4.15x+29.35=7.29x+189.21...
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