Mathematics, 11.10.2019 07:50 cranfordjacori
Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close parentheses plus open parentheses 6 plus 3 i.
Answers: 1
![\bf \cfrac{4i}{7+4i}\cdot \cfrac{7-4i}{7-4i}\implies \cfrac{4i(7-4i)}{(7+4i)(7-4i)}\implies \cfrac{28i-16i^2}{7^2-(4i)^2} \\\\\\ \cfrac{28i-16(-1)}{49-(4^2i^2)}\implies \cfrac{28i+16}{49-[16(-1)]}\implies \cfrac{16+28i}{49+16}\implies \cfrac{16+28i}{65} \\\\\\ \cfrac{16}{65}+\cfrac{28i}{65}](/tpl/images/0309/6774/3cc3e.png)
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Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close paren...
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