Two friends left school at the same time and drove in opposite directions. one friend averages 40 miles per hour and the other friend averages 35 miles per hour. when will they be 150 miles apart?

The two friends will be 150 miles apart in 2 hours

Step-by-step explanation:

The two friends left the school at the same time and drove in opposite directions. One of them have a speed of 40 miles per hour while the other have a speed of 35 miles per hour .

The both of them are moving apart at the rate  = 40 + 35 = 75 miles per hour

let

t = time at which they are 150 miles apart

speed = distance/time

time  = distance/speed

time = 150/75

time = 2 hours

The two friends will be 150 miles apart in 2 hours

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."