Afantasy board game makes use of four dice. the first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. if all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

2400

Step-by-step explanation:

Given : The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each.

To Find: If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

Solution:

No. of faces of first die = 6

No. of faces of second die = 4

No. of faces of third die = 10

No. of faces of fourth die = 10

Now we are supposed to find the the number of possible outcomes exist.

So, Number of possible outcomes if all the dice are thrown together :

=

=

Hence there are 2400 possible outcomes if all the dice are thrown together and their combination dictates a certain outcome of the game.

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

there is no points to select.

step-by-step explanation: