What is the length of each side of the square that had the same area as a rectangle that has a length of 16 ft and a width 12.25 ft

area of rectangle = 16 x 12.25 = 196 square feet

 area of a square is S^2

196=s^2

s=sqrt(196) = 14

length os side for square is 14 feet

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

i believe the answer is 323 ft

step-by-step explanation: