For a daily airline flight between two cities, the number of pieces of checked luggage has a mean of 380 and a standard deviation of 20. what number of pieces of checked luggage is 3 standard deviations above the mean?

The answer is 440 pieces of checked luggage

Step-by-step explanation:

Mean = 380

Standard deviation = 20

No. of pieces of checked luggage for 1 standard deviation = 20 pieces

Therefore, Mean for 3 standard deviations above the mean = 3 × 20 = 60

Now, number of pieces of checked luggage 3 standard deviations above the mean = Mean for 1 standard deviation + Mean for 3 standard deviations above the mean

⇒ 380 + 60 = 440 pieces

89

step-by-step explanation:

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: